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By my-assignmentexpert, my-assignmentexpert 化学代写 2022年4月15日

如果你也在怎样代写无机化学inorganic chemistry这个学科遇到相关的难题，请随时右上角联系我们的24/7代写客服。无机化学inorganic chemistry涉及到无机和有机金属化合物的合成和行为。这个领域涵盖了非碳基的化合物，这些化合物是有机化学的主题。这两门学科之间的区别远非绝对，因为有机金属化学的分支学科有很多重叠。它在化学工业的各个方面都有应用，包括催化、材料科学、颜料、表面活性剂、涂料、药物、燃料和农业。

无机化学inorganic chemistry许多无机化合物是离子化合物，由阳离子和阴离子通过离子键连接组成。盐（属于离子化合物）的例子有氯化镁MgCl2，它由镁的阳离子Mg2+和氯的阴离子Cl-组成；或氧化钠Na2O，它由钠的阳离子Na+和氧化阴离子O2-组成。在任何盐中，离子的比例是这样的：电荷相互抵消，因此大部分化合物是电中性的。离子由其氧化状态描述，其形成的难易程度可以从电离电位（阳离子）或从母元素的电子亲和力（阴离子）推断出来。

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我们提供的无机化学inorganic chemistry及其相关学科的代写，服务范围广, 其中包括但不限于:

代写隐藏

1 化学代写|无机化学作业代写INORGANIC CHEMISTRY代考|3,4–Diketocyclobutene dianion (C4O42−)

2 化学代写|无机化学作业代写inorganic chemistry代考|Delocalized π-bonding in C5O52−

3 化学代写|无机化学作业代写INORGANIC CHEMISTRY代考|Delocalized π-bonding in C6O62−

4 无机化学代写

5 化学代写|无机化学作业代写INORGANIC CHEMISTRY代考|3,4–DIKETOCYCLOBUTENE DIANIONC4这42−

6 化学代写|无机化学作业代写INORGANIC CHEMISTRY代考|DELOCALIZED Π-BONDING IN C5O52−

7 化学代写|无机化学作业代写INORGANIC CHEMISTRY代考|DELOCALIZED Π-BONDING IN C6O62−

8 概率论代考

8.1 离散数学代写

化学代写|无机化学作业代写inorganic chemistry代考|Topology of boranes (Lipscomb’s rule): s t y x four-digit coding of bonding in boranes

化学代写|无机化学作业代写INORGANIC CHEMISTRY代考|3,4–Diketocyclobutene dianion (C4O42−)

The formation of delocalized $\pi$-bonding in 3,4 -diketocyclobutene dianioncan be understood as follows:
(i) The anion contains a total of $42 \mathrm{e}[4 \times 4(4 \mathrm{C})+4 \times 6(40)+$ two negative charge $=$ 42e] valence electrons.
(ii) The formation of $8 \sigma_{\mathrm{L}}$ bonds $[4 \sigma(\mathrm{C}-\mathrm{C})$ and $4 \sigma(\mathrm{C}-\mathrm{O})]$ involving sp ${ }^{2}$ hybridization on each carbon and oxygen in $\mathrm{C}{4} \mathrm{O}{4}{ }^{2-}$ is shown in the hybridization scheme (Figure 2.47)
$4 \mathrm{C}{6}=1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{2} ; \quad$ Valence shell electr. confgn. $=2 \mathrm{~s}^{2} 2 \mathrm{p}^{2}$ (ground state) ; Valence shell electr. confgn. $=2 \mathrm{~s}^{1} 2 \mathrm{p}{\mathrm{x}}{ }^{1} 2 \mathrm{p}{\mathrm{y}}{ }^{1} 2 \mathrm{p}{\mathrm{z}}{ }^{1}$
(excited state) $\underbrace{2 p_{x}^{1} 2 p_{y}^{\mid} 2 p_{z}^{1}}{s p^{2}}$ hybridization $2 \mathrm{O}{8}=1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{4} ; \quad$ Valence shell electr. confgn. $=2 \mathrm{~s}^{2} 2 \mathrm{p}^{4}$
(ground state) $=2 \mathrm{~s}^{2} 2 \mathrm{p}{\mathrm{x}}{ }^{2} 2 \mathrm{p}{\mathrm{y}}{ }^{1} 2 \mathrm{p}{\mathrm{z}}{ }^{1}$ $2 \mathrm{O}{8}^{-}=1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{5}$; Valence shell electr. confgn. $=2 \mathrm{~s}^{2} 2 \mathrm{p}^{5} \quad \mathrm{sp}^{2}$ hybridization
(ground state)
$$
=\underbrace{2 \mathrm{~s}^{2} 2 \mathrm{p}{\mathrm{x}}^{2} 2 \mathrm{p}{\mathrm{y}}{ }^{1} 2 \mathrm{p}{\mathrm{z}}{ }^{2}}{\mathrm{sp}^{2} \text { hybridization }}
$$

化学代写|无机化学作业代写inorganic chemistry代考|Delocalized π-bonding in C5O52−

The formation of delocalized $\pi$-bonding in croconate ion, $\mathrm{C}{5} \mathrm{O}{5}{ }^{2-}$, can be understood as follows:
(i) The anion contains a total of $52 \mathrm{e}[5 \times 4(5 \mathrm{C})+5 \times 6(50)+$ two -ve charge $=52 \mathrm{e}]$ valence electrons.
(ii) The formation of $10 \sigma_{\mathrm{L}}$ bonds $[5 \sigma(\mathrm{C}-\mathrm{C})$ and $5 \sigma(\mathrm{C}-\mathrm{O})]$ involving sp ${ }^{2}$ hybridization on each carbon and oxygen in $\mathrm{C}{5} \mathrm{O}{5}{ }^{2-}$ is shown in Figure $2.50$.

\begin{aligned}
&5 \mathrm{C}{6}=1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{2} ; \quad \text { Valence shell electr. confgn. }=2 \mathrm{~s}^{2} 2 \mathrm{p}^{2}\ &\text { (ground state) }\ &\text { ; Valence shell electr. confgn. }=2 \mathrm{~s}^{1} 2 \mathrm{p}{\mathrm{x}}^{1} 2 \mathrm{p}{\mathrm{y}}^{1} 2 \mathrm{p}{\mathrm{z}}^{1}\
&\text { (excited state) } \underbrace{2 \mathrm{e}^{2}}{\mathrm{sp}^{2}} \text { hybridization }\ &3 \mathrm{O}{8}=1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{4} ; \quad \text { Valence shell electr. confgn. }=2 \mathrm{~s}^{2} 2 \mathrm{p}^{4}\
&\text { (ground state) }=\underbrace{2 \mathrm{~s}^{2} 2 \mathrm{p}{\mathrm{x}}^{2} 2 \mathrm{p}{\mathrm{y}}{ }^{1} 2 \mathrm{p}{\mathrm{z}}{ }^{1}}{s p^{2} \text { hybridization }}\
&2 \mathrm{O}{8}^{-}=1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{5} ; \quad \text { Valence shell electr. confgn. }=2 \mathrm{~s}^{2} 2 \mathrm{p}^{5}\ &\text { (ground state) }\ &=\underbrace{2 \mathrm{~s}^{2} 2 \mathrm{p}{\mathrm{x}}^{2} 2 \mathrm{p}{\mathrm{y}}^{1}}{\mathrm{sp}^{2} \text { hybridization }} 2 \mathrm{p}_{\mathrm{z}}^{2}
\end{aligned}

化学代写|无机化学作业代写INORGANIC CHEMISTRY代考|Delocalized π-bonding in C6O62−

The formation of delocalized $\pi$-bonding in $\mathbf{C}{6} \mathbf{O}{6}{ }^{2-}$ can be understood as follows:
(i) The anion contains a total of $62 \mathrm{e}[6 \times 4(6 \mathrm{C})+6 \times 6(50)+$ two -ve charge $=62 \mathrm{e}]$ valence electrons.
(ii) The formation of $12 \sigma_{\mathrm{L}}$ bonds $[6 \sigma(\mathrm{C}-\mathrm{C})$ and $6 \sigma(\mathrm{C}-\mathrm{O})]$ involving $\mathrm{sp}^{2}$ hybridization on each carbon and oxygen in $\mathrm{C}{6} \mathrm{O}{6}{ }^{2-}$ is shown in Figure $2.53$
$6 \mathrm{C}{6}=1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{2} ; \quad$ Valence shell electr. confgn. $\quad=2 \mathrm{~s}^{2} 2 \mathrm{p}^{2}$ (ground state) ; Valence shell electr. confgn. $\quad=\underbrace{2 \mathrm{~s}^{1} 2 \mathrm{p}{\mathrm{x}}{ }^{1} 2 \mathrm{p}{\mathrm{y}}{ }^{1}}{\text {(excited state) }}{ }^{\mathrm{sp}} \mathrm{p}{\mathrm{z}}{ }^{1}$ hybridization $4 \mathrm{O}{8}=1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{4} ; \quad$ Valence shell electr. confgn. $=2 \mathrm{~s}^{2} 2 \mathrm{p}^{4}$
(ground state) $=2 \mathrm{~s}^{2} 2 \mathrm{p}{\mathrm{x}}{ }^{2} 2 \mathrm{p}{\mathrm{y}}{ }^{1} 2 \mathrm{p}{\mathrm{z}}{ }^{1}$ $2 \mathrm{O}{8}^{-}=1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{5} ; \quad$ Valence shell electr. confgn. $=2 \mathrm{~s}^{2} 2 \mathrm{p}^{5}$
(ground state)
$=2 \mathrm{~s}^{2} 2 \mathrm{p}{\mathrm{x}}^{2} 2 \mathrm{p}{\mathrm{y}}{ }^{1} 2 \mathrm{p}_{\mathrm{z}}{ }^{2}$
$\mathrm{sp}^{2}$ hybridization

化学代写|无机化学作业代写inorganic chemistry代考|Delocalized π-bonding in cyclic ions

无机化学代写

化学代写|无机化学作业代写INORGANIC CHEMISTRY代考|3,4–DIKETOCYCLOBUTENE DIANIONC4这42−

离域的形成圆周率3,4-二酮环丁烯双阴离子中的-键合可以理解如下：
一世阴离子共含有42和[4×4(4C)+4×6(40)+两个负电荷=42e] 价电子。(ii) The formation of $8 \sigma_{\mathrm{L}}$ bonds $[4 \sigma(\mathrm{C}-\mathrm{C})$ and $4 \sigma(\mathrm{C}-\mathrm{O})]$ involving sp ${ }^{2}$ hybridization on each carbon and oxygen in $\mathrm{C}{4} \mathrm{O}{4}{ }^{2-}$ is shown in the hybridization scheme (Figure 2.47)
$4 \mathrm{C}{6}=1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{2} ; \quad$ Valence shell electr. confgn. $=2 \mathrm{~s}^{2} 2 \mathrm{p}^{2}$ (ground state) ; Valence shell electr. confgn. $=2 \mathrm{~s}^{1} 2 \mathrm{p}{\mathrm{x}}{ }^{1} 2 \mathrm{p}{\mathrm{y}}{ }^{1} 2 \mathrm{p}{\mathrm{z}}{ }^{1}$
(excited state) $\underbrace{2 p_{x}^{1} 2 p_{y}^{\mid} 2 p_{z}^{1}}{s p^{2}}$ hybridization $2 \mathrm{O}{8}=1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{4} ; \quad$ Valence shell electr. confgn. $=2 \mathrm{~s}^{2} 2 \mathrm{p}^{4}$
(ground state) $=2 \mathrm{~s}^{2} 2 \mathrm{p}{\mathrm{x}}{ }^{2} 2 \mathrm{p}{\mathrm{y}}{ }^{1} 2 \mathrm{p}{\mathrm{z}}{ }^{1}$ $2 \mathrm{O}{8}^{-}=1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{5}$; Valence shell electr. confgn. $=2 \mathrm{~s}^{2} 2 \mathrm{p}^{5} \quad \mathrm{sp}^{2}$ hybridization
(ground state)
$$
=\underbrace{2 \mathrm{~s}^{2} 2 \mathrm{p}{\mathrm{x}}^{2} 2 \mathrm{p}{\mathrm{y}}{ }^{1} 2 \mathrm{p}{\mathrm{z}}{ }^{2}}{\mathrm{sp}^{2} \text { hybridization }}
$$

化学代写|无机化学作业代写INORGANIC CHEMISTRY代考|DELOCALIZED Π-BONDING IN C5O52−

离域的形成圆周率-croconate ion中的键合\pi$-bonding in croconate ion, $\mathrm{C}{5} \mathrm{O}{5}{ }^{2-}$, can be understood as follows:
(i) The anion contains a total of $52 \mathrm{e}[5 \times 4(5 \mathrm{C})+5 \times 6(50)+$ two -ve charge $=52 \mathrm{e}]$ valence electrons.
(ii) The formation of $10 \sigma_{\mathrm{L}}$ bonds $[5 \sigma(\mathrm{C}-\mathrm{C})$ and $5 \sigma(\mathrm{C}-\mathrm{O})]$ involving sp ${ }^{2}$ hybridization on each carbon and oxygen in $\mathrm{C}{5} \mathrm{O}{5}{ }^{2-}$ is shown in Figure $2.50$.

化学代写|无机化学作业代写INORGANIC CHEMISTRY代考|DELOCALIZED Π-BONDING IN C6O62−

离域的形成圆周率-结合在 $\pi$-bonding in $\mathbf{C}{6} \mathbf{O}{6}{ }^{2-}$ can be understood as follows:
(i) The anion contains a total of $62 \mathrm{e}[6 \times 4(6 \mathrm{C})+6 \times 6(50)+$ two -ve charge $=62 \mathrm{e}]$ valence electrons.
(ii) The formation of $12 \sigma_{\mathrm{L}}$ bonds $[6 \sigma(\mathrm{C}-\mathrm{C})$ and $6 \sigma(\mathrm{C}-\mathrm{O})]$ involving $\mathrm{sp}^{2}$ hybridization on each carbon and oxygen in $\mathrm{C}{6} \mathrm{O}{6}{ }^{2-}$ is shown in Figure $2.53$
$6 \mathrm{C}{6}=1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{2} ; \quad$ Valence shell electr. confgn. $\quad=2 \mathrm{~s}^{2} 2 \mathrm{p}^{2}$ (ground state) ; Valence shell electr. confgn. $\quad=\underbrace{2 \mathrm{~s}^{1} 2 \mathrm{p}{\mathrm{x}}{ }^{1} 2 \mathrm{p}{\mathrm{y}}{ }^{1}}{\text {(excited state) }}{ }^{\mathrm{sp}} \mathrm{p}{\mathrm{z}}{ }^{1}$ hybridization $4 \mathrm{O}{8}=1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{4} ; \quad$ Valence shell electr. confgn. $=2 \mathrm{~s}^{2} 2 \mathrm{p}^{4}$
(ground state) $=2 \mathrm{~s}^{2} 2 \mathrm{p}{\mathrm{x}}{ }^{2} 2 \mathrm{p}{\mathrm{y}}{ }^{1} 2 \mathrm{p}{\mathrm{z}}{ }^{1}$ $2 \mathrm{O}{8}^{-}=1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{5} ; \quad$ Valence shell electr. confgn. $=2 \mathrm{~s}^{2} 2 \mathrm{p}^{5}$
(ground state)
$=2 \mathrm{~s}^{2} 2 \mathrm{p}{\mathrm{x}}^{2} 2 \mathrm{p}{\mathrm{y}}{ }^{1} 2 \mathrm{p}_{\mathrm{z}}{ }^{2}$
$\mathrm{sp}^{2}$ 杂交